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The Research of Solution of Levinson — Smith Equation

ISSN 1812-3368. Вестник МГТУ им. Н.Э. Баумана. Сер. Естественные науки. 2017. № 1

19

Corollary 1, the set

\

 

is positively invariant, and, therefore, so are all of its

connected components

,

I

.

I

From above, we conclude the following.

Statement 2.

All the sets

,

I

,

I

are positively invariant.

For an arbitrary

> 0

C

, denote by

( )

U C

the subset defined by the inequalities

> 0

x

and

( )< < ( )

x y x C

  

and by

( )

U C

the subset defined by the inequalities < 0

x

and

( ) < < ( ).

x C y x

 



The following theorem is the main result of the paper.

Theorem 1.

Suppose that the system

(5)

satisfies

>0 inf{ ( ) :

( )}> 0,

inf{ ( ) :

( )}>0.

C

f p p U C

f p p U C

(6)

If

:

( ( ), ( )),

t x t y t

 

0,

t

is an arbitrary trajectory, then

enters the localizing set

at some time

0

0

t

and then never leaves it, or

is completely located outside the

localizing set

,

*

( ( ))

,

t

h t

G



 

dist( ( ), )

0

t

t



  

(dist( ,

)

P M

is the

distance from the point P to the set M) and one of the following three conditions holds

1)

( )

;

t

t

p



  

2)

( )

t

x t





and the integral

*

0

( )

G G x dx



is convergent;

3)

( )

t

x t





and the integral

0

*

( )

G G x dx



is convergent.

If the trajectory enters the localizing set

at some time

0

0,

t

then it never

leaves it since the set

is positively invariant.

Suppose that

is completely located outside the localizing set

.

This means

that

is contained in the set

U

and, therefore, in one of its connected components

U

and

.

U

Then, there are two possible cases

1)

 

U

and, thus,

 

= > ( ) 0,

x y x

on

,

i. e.

( )

x t

is strictly increasing and,

hence,



   

*

( )

( ;

];

t

x t

x

2)

 

U

and, thus,

 

= < ( ) 0

x y

x

on

,

i. e.

( )

x t

is strictly decreasing

and, hence,



   

*

( )

[ ;

).

t

x t

x

In

both

cases,

the

function

( )

x t

is

strictly

monotonous,



   

*

( )

[ ;

],

t

x t

x

and the function

( )

y t

is nonzero and of constant sign

on

.

The set

is defined by each of two equivalent inequalities

 

( )

y x

and

*

.

h G

Hence,

> ( )

y x

and

*

>

h G

on

.

By Statement 1, the function

h

is decreasing

on

.

Thus,



   

*

*

( ( ))

[ ;

)

t

h t

h G

and

*

h h

on

.

Lemma 1.

If

is completely located outside the localizing set

and

*

x

is a finite

number, then the trajectory

tends to some point



p

and, also,



  

dist( ( ), )

0,

t

t



 

*

*

( ( ))

= .

t

h t

h G