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O.G. Styrt, A.P. Krishchenko

20

ISSN 1812-3368. Вестник МГТУ им. Н.Э. Баумана. Сер. Естественные науки. 2017. № 1

We have



 

 

def

2

*

*

( ( )) = 2( ( ( )) ( ( )))

= 2(

( )).

t

y t

h t

G x t

d h G x

Since the

function

( )

y t

is of constant sign,



   

*

( )

( ;

).

t

y t

y

Consequently, the

trajectory

tends to the point

def

* *

2

= ( , )

.

p x y

Note that

 

0

{ }.

p

Ox

Besides,

 

U

implying

,

p U

  

{ } = .

p U Ox

Thus,



   

( )

= { }

t

t

p

Ox

and, therefore,

*

( ) = .

h p G

Also,



*

*

= ( ( )) = ( ) = .

lim

t

h

h t

h p G

We see that, if

is completely located outside the localizing set

and

*

x

is a

finite number, then the first case of Theorem 1 takes place.

Now suppose that

*

| |= .

x

Statement 3.

If

2

( , )

x y

and

 

def

*

= ( , )

0,

C h x y G then

  

2 ( ).

y

C x

We have

    

2

2

2

= 2( ( , ) ( )) = 2 ( ( ))

2 ( ) ,

y h x y G x C x

C x

 

2

y

C



( ).

x

Proposition 1.

If

is completely located outside the localizing set

,

then

    

*

( ) <| |

2(

) ( )

x y

h G x

on

.

On

,

we have

> ( )

y x

and, also,

*

> ,

h G

*

> 0,

h G

and, by Statement 3,

  

*

2(

) ( ).

y

h G x

Corollary 3.

If

is completely located outside the localizing set

,

then there

exists a number

> 0

C

such that

 

| |< ( )

y x C

on

once

0.

t

The proof follows from Proposition 1 and decreasing of the function

h

on

.

Lemma 2.

If

is completely located outside the localizing set

and



*

=

x



*

( = ),

x

then there exist numbers

0

0

t

and

> 0

C

such that, for each

0

,

t t

we

have

 

( )

( )

t U C

 

( ( )

( )).

t U C

By Corolla

r

y 3, there exists a number

> 0

C

such that

 

 

( ) < < ( )

x C y x C

on

once

0.

t

Suppose that



*

= .

x

Then

 

U

and, thus,

> ( )

y x

on

.

Besides, there

exists a number

0

0

t

such that > 0

x

on

once

0

.

t t

If

( , ) = ( ),

x y t

0

,

t t

then

> 0

x

and

  

( )< < ( )

x y x C

implying

( , )

( ).

x y U C

Now assume that



*

= .

x

Then

 

U

and, thus,



< ( )

y

x

on

.

Besides,

there exists a number

0

0

t

such that < 0

x

on

once

0

.

t t

If

( , ) = ( ),

x y t

0

,

t t

then < 0

x

and

 



( ) < < ( )

x C y

x

implying

( , )

( ).

x y U C

Lemma 3.

If the condition (6) holds, the trajectory

is completely located outside

the localizing set

,

and

*

= ,

x

then

*

*

= ,

h G

and the integral

*

*

0

( )

x

G G x dx

is

convergent.