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and the only possible passages between

Ω

−

and

Ω

+

are

 

+

+

+

−

 

←

 

+

−

+

−

 

→

 

+

−

−

−

 

,

 

−

−

+

+

 

←

 

+

−

+

+

 

→

 

+

+

+

+

 

,

 

−

−

−

+

 

←

 

+

−

−

+

 

→

 

+

−

−

−

 

,

 

+

+

+

+

 

←

 

+

+

−

+

 

→

 

+

+

−

−

 

,

 

−

−

−

+

 

←

 

−

+

−

+

 

→

 

−

+

+

+

 

,

 

+

+

−

−

 

←

 

−

+

−

−

 

→

 

−

−

−

−

 

,

 

+

+

+

−

 

←

 

−

+

+

−

 

→

 

−

+

+

+

 

,

 

−

−

−

−

 

←

 

−

−

+

−

 

→

 

−

−

+

+

 

,

always from

Ω

−

to

Ω

+

.

So, any trajectory generated by a non-trivial solution can perform only

one passage between

Ω

−

and

Ω

+

,

which can be only from

Ω

−

to

Ω

+

.

I

Lemma 4.

There exist trajectories of all three types mentioned in

Lemma 3, namely

•

trajectories lying completely in

Ω

−

;

•

trajectories lying completely in

Ω

+

;

•

trajectories with a single passage

Ω

−

→

Ω

+

.

J

Any solution to (1) with initial data corresponding to a point from

Ω

−

∩

Ω

+

generates a trajectory of the 3rd type. E.g., the solution with initial

data

y

0

(0) = 0

, y

(0) =

y

00

(0) =

y

000

(0) = 1

generates a trajectory with the

passage

 

+

−

+

+

 

⊂

Ω

−

→

 

+

+

+

+

 

⊂

Ω

+

.

If there exists a solution

y

(

x

)

to (1) generating a trajectory lying

completely in

Ω

−

,

then the function

z

(

x

) =

y

(

−

x

)

is also a solution

10

ISSN 1812-3368. Вестник МГТУ им. Н.Э. Баумана. Сер. “Естественные науки”. 2015. № 2